Re: [Math4u] Arithmatic sum

 

Assume the cost of production = $1

Retail selling price = $1 + p/100

Discount = (Retail selling price ) * q/100= ($1 + p/100) * q/100

Actual Selling Price = Retail selling price - discount

= ($1 + p/100) - ($1 + p/100) * q/100

profit = actual selling price - cost of production

= [($1 + p/100) - ($1 + p/100) * q/100] - $1

%profit = profit * 100 / cost

= 100*{[($1 + p/100) - ($1 + p/100) * q/100] - $1}

= 100*{[($1 + p/100) * (1-  q/100 ) ] - $1}

= {(100 + p) * (100-  q )  - 10,000}/100  answer

 

Check:

let cost = $1.00

p = 20

q = 25

retail selling price = $1.20

discounted selling price = $0.90

percent profit = (-0.10/1.00)*100 = -10%

{(100 + p) * (100-  q )  - 10,000}/100

={(100 + 20) * (100-  25 )  - 10,000}/100

={(120) * (75)  - 10,000}/100

={ 9,000  - 10,000}/100

={ -10000} /100

= -10 profit or 10% loss  ok

regards,

Brian Jensen

 

 

----- Original Message -----

From: jn_mdesai

To: Math4u@yahoogroups.com

Sent: Friday, October 05, 2007 10:01 AM

Subject: [Math4u] Arithmatic sum

A manufacturer lists the retail selling price of an article at p% more
than the cost of production. If he gives discount of q% to the
retailers, what is his percentage of profit?

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