RE: [Math4u] problem1

For n >= 9:

 

n >= 3n^(1/2) > n^(1/2) + n^(1/3) + n^(1/4)

 

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From: Math4u@yahoogroups.com [mailto:Math4u@yahoogroups.com] On Behalf Of Sarthak Chandra
Sent: 08 October 2007 10:59
To: mathematics; compute@onelist.com; dlsu_math_circle@yahoogroups.com; harmonicanalysis@yahoogroups.com; india-math@yahoogroups.com; math4u@yahoogroups.com; math_club@yahoogroups.com; mathc@yahoogroups.com; matholympiad2@yahoogroups.com; maths@yahoogroups.com; numbertheory@yahoogroups.com; ooclubinfinityoo@yahoogroups.com; sphericalcow@yahoogroups.com; theartofcomputerprogramming@yahoogroups.com; truenumber@yahoogroups.com
Subject: [Math4u] problem1

prove that

n>n^(1/2)+n^(1/3)+n^(1/4)                       for all integers n >= 9

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