Wednesday, October 03, 2007

RE: [Math4u] Re: Maxima & Minima

I think the point is more to do with definitions than anything else.
 
If I understand correctly, according to Sanjeev:
At a local maximum, you can choose a small area around the point, where that point is higher than every other point in the set.
At a local minimum, you can choose a small area around the point, where that point is lower than every other point in the set.
 
So, Sanjeev constructed a case where there is a plateau - no point is lower than its' neighbour.  So, while it is true that between two local maxima, there are points with a minimum value, there does not need to be a local minimum.
 
However, as to whether this is a valid definition or not, I leave to the reader.  I reckon Wikipedia's and Mathworld's definitions would allow all points in a plateau to be minima, contradicting Sanjeev, but in maths, you start with a set of lies, and build elaborate structures, so it just comes down to what lies we tell ourselves! 

--
         CH3        Stephen Tavener
          |         DigiText Programmer, BBC News, New Media.
          N
         / \        Room BC3 xtn (020 800)84739
   N----C   C==O    Broadcast Centre, 201 Wood Lane, London. W12 7TP
  ||   ||   |
  ||   ||   |       mailto:Stephen.Tavener@bbc.co.uk (Work)
  CH    C   N--CH3  mailto:mrraow@gmail.com (Home)
    \  / \ /
     N    C         http://www.scat.demon.co.uk/ (Games)
     |    || 
    CH3   O         Baby pictures:
http://rainbot.pwp.blueyonder.co.uk/Katiefrog/group.jpg

 


From: Math4u@yahoogroups.com [mailto:Math4u@yahoogroups.com] On Behalf Of Brian E. Jensen
Sent: 02 October 2007 20:06
To: Math4u@yahoogroups.com
Subject: Re: [Math4u] Re: Maxima & Minima

 
 
max at (pi/2,1)
min at (3pi/2,-1)
max at (5pi/2,1)
min at (7pi/2, -1)
max at 9pi/2,1)
It looks to me like the statement is proved true by Sanjiva's example.
regards, Brian
 
----- Original Message -----
Sent: Tuesday, October 02, 2007 3:42 AM
Subject: RE: [Math4u] Re: Maxima & Minima

Hi,
1.
The statement of my question is proved false by the
following example:-
f(x)=sinx, x<=3*pi/2
=-1, 3*pi/2<x<7*pi/2
=sinx, x>=7*pi/2.
This function f(x) is defined for all real x, is
continuous & differentiable for all real x and has
local maximas at x=pi/2 and x=9*pi/2, but there is no
local minima betweem pi/2 and 9*pi/2. Therefore, the
initial statement is FALSE.
2.
Moral of the story:- "Never use common sense in
Mathematics, always think from the definitions".
Sanjiva

--- Stephen Tavener <stephen.tavener@bbc.co.uk> wrote:

> Hmmm... what about a function which has a plateau
> between two local
> maximae?
>
> At this late remove, I can't remember all my
> definitions, but I think we
> can get away with a function like:
>
> f(x) = {
> g(x) for x <= k1
> h(x) for k1 < x <= k2
> i(x) for k2 < x
> }
>
> define h(x) to be 0 at all values, and choose
> suitable cubic equations
> for g(x) and i(x) such that g(k1) = 0, i(k2) = 0,
> g'(k1) = 0, i'(k2) =
> 0, and g(x) and i(x) have suitable maximae.
>
> If memory serves, this should meet the definitions
> of continuous and
> differentiable at all points, but somebody who has
> done a maths degree
> more recently than 20 years ago (ouch) can tell me
> if I'm wrong!
>
>
> --
> CH3 Stephen Tavener
> | DigiText Programmer, BBC News,
> New Media.
> N
> / \ Room BC3 xtn (020 800)84739
> N----C C==O Broadcast Centre, 201 Wood Lane,
> London. W12 7TP
> || || |
> || || | mailto:Stephen.Tavener@bbc.co.uk
> (Work)
> CH C N--CH3 mailto:mrraow@gmail.com (Home)
> \ / \ /
> N C http://www.scat.demon.co.uk/
> (Games)
> | ||
> CH3 O Baby pictures:
>
http://rainbot.pwp.blueyonder.co.uk/Katiefrog/group.jpg
>
>
>
>
> ________________________________
>
> From: Math4u@yahoogroups.com
> [mailto:Math4u@yahoogroups.com] On Behalf
> Of Brian E. Jensen
> Sent: 01 October 2007 17:38
> To: Math4u@yahoogroups.com
> Subject: Re: [Math4u] Re: Maxima & Minima
>
>
>
> I don't have time to figure out what Jim FitzSimons,
> who is very
> intelligent said. But the initial statement is true:
>
>
> If a function is differentiable over the whole
> length, then you can't
> have two maximums without having a minimum between
> and you can't have
> two minimums without having a maximum between.
>
> More generally, the function only needs to be
> continuous for this to be
> true. Not all continuous functions are
> differentiable, but all
> differentiable functions are continuous, for
> example:
>
> y = absolute value of x.
>
> Regards, Brian
>
>
>
> ----- Original Message -----
> From: w7anf <mailto:cherry@getnet.net>
> To: Math4u@yahoogroups.com
> <mailto:Math4u@yahoogroups.com>
> Sent: Sunday, September 30, 2007 8:49 PM
> Subject: [Math4u] Re: Maxima & Minima
>
>
> A real function is said to be differentiable at a
> point if its
> derivative
> exists at that point. The notion of
> differentiability can also
> be
> extended
> to complex functions (leading to the Cauchy-Riemann
> equations
> and
> the theory
> of holomorphic functions), although a few
> additional subtleties
> arise in
> complex differentiability that are not present in
> the real case.
>
>
> Amazingly, there exist continuous functions which
> are nowhere
> differentiable.
> Two examples are the Blancmange function and
> Weierstrass
> function.
> Hermite
> (1893) is said to have opined, "I turn away with
> fright and
> horror
> from this
> lamentable evil of functions which do not have
> derivatives"
> (Kline 1990, p. 973).
>
> The derivative of a function f(x) with respect to
> the variable x
> is
> defined as
>
> f'(x)=lim((f(x+h)-f(x))/h,h,0) (6)
>
> but may also be calculated more symmetrically as
>
> f'(x)=lim((f(x+h)-f(x-h))/(2*h),h,0) (7)
>
> provided the derivative is known to exist.
>
> It should be noted that the above definitions refer
> to "real"
> derivatives,
> i.e., derivatives which are restricted to
> directions along the
> real
> axis.
> However, this restriction is artificial, and
> derivatives are
> most
> naturally
> defined in the complex plane, where they are
> sometimes
> explicitly
> referred
> to as complex derivatives. In order for complex
> derivatives to
> exist, the
> same result must be obtained for derivatives taken
> in any
> direction
> in the
> complex plane. Somewhat surprisingly, almost all of
> the
> important
> functions
> in mathematics satisfy this property, which is
> equivalent to
> saying
> that
> they satisfy the Cauchy-Riemann equations.
>
> These considerations can lead to confusion for
> students because
> elementary
> calculus texts commonly consider only "real"
> derivatives, never
> alluding to
> the existence of complex derivatives, variables, or
> functions.
> For
> example,
> textbook examples to the contrary, the "derivative"
>
> (read: complex derivative) d abs(z)/dz of the
> absolute value
> function abs(z)
> does not exist because at every point in the
> complex plane, the
> value of the
> derivative depends on the direction in which the
> derivative is
> taken
> (so the
> Cauchy-Riemann equations cannot and do not hold).
> However, the
> real
> derivative (i.e., restricting the derivative to
> directions along
> the
> real
> axis) can be defined for points other than x=0 as
>
=== message truncated ===

Sanjiva Dayal, B.Tech.(I.I.T. Kanpur)
Address:A-602, Twin Towers, Lakhanpur, Kanpur-208024, INDIA.
Phones:+91-512-2581532,2581426.
Mobile:9415134052
Business email:sanjivadayal@yahoo.com
Personal email:sanjivadayal@hotmail.com

__________________________________________________________
Don't let your dream ride pass you by. Make it a reality with Yahoo! Autos.
http://autos.yahoo.com/index.html



http://www.bbc.co.uk
This e-mail (and any attachments) is confidential and may contain personal views which are not the views of the BBC unless specifically stated.
If you have received it in error, please delete it from your system.
Do not use, copy or disclose the information in any way nor act in reliance on it and notify the sender immediately.
Please note that the BBC monitors e-mails sent or received.
Further communication will signify your consent to this.
__._,_.___

Your email settings: Individual Email|Traditional
Change settings via the Web (Yahoo! ID required)
Change settings via email: Switch delivery to Daily Digest | Switch to Fully Featured
Visit Your Group | Yahoo! Groups Terms of Use | Unsubscribe

__,_._,___

No comments: