numbers. The numbers are:
1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10.
If anybody has seen the British TV show, Countdown, then this is
where the problem comes from.
How much more likely is it of choosing 1, 3, 4, 5, 6, 7 compared with
1, 1, 2, 2, 3, 3?
The next question (which probably helps solve the above) is:
There are 6! ways of arranging 1, 3, 4, 5, 6, 7 in some order. How
many ways are there of arranging 1, 1, 2, 2, 3, 3 in some order? This
kind of thing I struggle with as we have repeated numbers. Do we just
do 6! divided by 3 as there are 3 repeats? I don't have the right
intuition for combinations.
Any explanation as to how you worked these out would be appreciated.
I don't understand combinations so don't feel like you're patronising
if you explain fully!!
Kirk
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