255 ways to select a pair.
255/495=17/33
None of the answers are correct.
Jim FitzSimons
--- In Math4u@yahoogroups.com, "Alex Chandra" <mbs@...> wrote:
>
> Bill has a small deck of 12 playing cards made up of only 2 suits
of 6
> cards each. Each of the 6 cards within a suit has a different
value
> from 1 to 6; thus, there are 2 cards in the deck that have the
same value.
>
> Bill likes to play a game in which he shuffles the deck, turns
over 4
> cards, and looks for pairs of cards that have the same value. What
is
> the chance that Bill finds at least one pair of cards that have the
> same value?
>
> a. 8/33
> b. 62/165
> c. 14/33
> d. 103/165
> e. 25/33
>
Yahoo! Groups Links
<*> To visit your group on the web, go to:
http://groups.yahoo.com/group/Math4u/
<*> Your email settings:
Individual Email | Traditional
<*> To change settings online go to:
http://groups.yahoo.com/group/Math4u/join
(Yahoo! ID required)
<*> To change settings via email:
mailto:Math4u-digest@yahoogroups.com
mailto:Math4u-fullfeatured@yahoogroups.com
<*> To unsubscribe from this group, send an email to:
Math4u-unsubscribe@yahoogroups.com
<*> Your use of Yahoo! Groups is subject to:
No comments:
Post a Comment