teachers who work with third and fourth grade, by mistake. I'm forwarding
it to the Math4U group instead...
--- In MathMatters3-4@yahoogroups.com, Ashok Hari <grpashok@...> wrote:
Dear all,
I am studying at Open University so I don't have a proper teacher who can teach me,
particularly math. Because of that I am studying math by myself. While I go through the
math I find some doubts. Please and kindly give your ideas and notes to clear my doubts.
Problem,
A box contains twice as many red marbles as green marbles. One marble is
drawn at random from the box and is replaced; then a second marble is drawn at random
from the box. If both marbles are green you win Rs:50; if both marbles are red you loose
Rs:10; and if the marbles are of different colours, then you neither loose nor win.
Determine the probability distribution for the amount you win or loose?
Solution:-
Say X denote the amount you win(+) or loose(-); ie.X=+50 or -10
The probability that both marbles are green is 1/9 i.e P[X=+50]=1/9
The probability that both marbles are red is 4/9 i.e. P[X=-10]=4/9
The probability that marbles are of different colours is 4/9 ie. P[X=0]=4/9
Thus, the probability distribution is given by following table.
Amount(in Rs won(+) or lost(-))
Probability
+50
1/9
0
4/9
-10
4/9
My Advance Thanks,
Regards,
H.Ashok.
--- End forwarded message ---
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