RE: [Math4u] Simple percentage problem

The question seems poorly worded. 

For a start, sounds like it's megabits per second, rather than megabits.

Secondly, if a solution is possible, then we need to know the amount of bandwidth used, rather than the amount of bandwidth available. 

 

With these two corrections in mind...

 

Bandwidth used is:

 

DSL * 1.46 + Cable * 4.16 = 1335.31

 

Also,

 

3.7 * DSL = Cable

 

So, substitute the second equation into the first equation calculate the number of DSL users, then it's easy to calculate the number of Cable users.

 

Good luck,

 

 

 

Stephen

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From: Math4u@yahoogroups.com [mailto:Math4u@yahoogroups.com] On Behalf Of pwn_escobar
Sent: 26 November 2007 15:30
To: Math4u@yahoogroups.com
Subject: [Math4u] Simple percentage problem

I'm absolutely stumped on this. In my mind it is very simple but I
can't get it.

An internet service provider has 1335.31 megabits available. A single
DSL subscriber requires 1.46 megabits. A single Cable subscriber
requires 4.16 megabits. There are 3.7 times as many Cable subscribers
than DSL subscribers. How many Cable/DSL subscribers are there?

Help appreciated

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