>
> Hey everyone, I need some help. I have an Honors exam
> in Physics and I need to understand how to do these
> problems. I missed the nots from last class and need to
> catch up. If possible, please respond back soon.
> Thanks!
> A runner with a good awareness of her pace runs along a
> path of unknown length at a speed of 0.20 mi/min and
> then walks back to her starting point at a speed of
> 0.05 mi/min. She neglects to note her time for each
> part of her path, but she does measure the total round
> trip time to be 50.0 min. How far has she run?
She travels for .2x + .05x (going x mi and return)
.2x + .05x = 50 (total time), and solve
[Brian's correction: time=x/.2+x/.05=50]
> Two sprinters run a 100. meter dash, with the winner
> finishing in 10.0 sec. If the other runner was 1.00 m
> behind the winner at the finish, how long did it take
> her to run the 100 m.
The winner goes 100m in 10 sec. The second runner goes
99m in 10 sec.
She goes 9.9m/sec, or 100/9.9 seconds for the course.
> Two towns, A and B, are 200 miles apart. Car 1 starts
> from town A and, at the same time, car 2 starts from
> town B. They move toward each other with constant
> speeds: car 1 at 50 mph, car 2 at 40 mph. Where do the
> cars meet? How long does it take for them to meet?
50t + 40t = 200 (They each travel t hours)
Car 1 goes 50t miles, while car 2 goes 40t miles.
> If the distance an object traveled is plotted on a
> graph vs. time, what physical quantity does that slope
> represent?
That would be rate, or D/T
> If the distance two objects traveled is plotted on a
> graph vs. time, how could you tell which object is
> moving faster?
The curve with the greatest slope is travelling faster.
> How does the distance vs. time graph of an object that
> is accelerating compare to the distance vs. time graph
> of an object that is undergoing uniform motion?
The accelerating object presents a curve, usually
parabolig, while the one moving at constant speed is a
straight line.
> Find the horizontal and vertical velocity component of
> a velocity of 50.0 m/s, 35.0°.
Vertical velocity is 50 x sin 35º
Horizontal distance is 50 x cos 35º
> Find the horizontal and vertical velocity of an object
> that moves from (5.00m, 3.50m) to (-2.00m, 4.00m) in
> 2.50 seconds. Find the magnitude and direction of the
> velocity.
HD is (5 - (-2))/2.5
VD is (3.5 - 4)/2.5
________________________________________
KrazyKyngeKorny(Krazy, not stupid)
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