Monday, September 24, 2007

[Math4u] Re: Maxima & Minima

Hi:

False

Proof: While there are infinitely many counter examples, consider f(x)=-x^2 for all real x.  Clearly f is differentiable on its entire domain.  Yet f(x) has no minima whatsoever, thereby completing the proof.    

Regards,

Rich B.

--- In Math4u@yahoogroups.com, "sanjivadayal" <sanjivadayal@...> wrote:
>
> Whether the following statement is true or false?
> "If f(x) is a differentiable function, then there must be at least one
> minima between two maximas".
>

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